What is the derivative of x^2+sqrt(x) ?

The derivative of x^2+sqrt(x) is 2x+1/(2sqrt(x))

What is the first derivative of x^2+sqrt(x) ?

The first derivative of x^2+sqrt(x) is 2x+1/(2sqrt(x))

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\frac{d}{d x} (x^{2} + x)

2 x + \frac{1}{2 x}

Solution steps

\frac{d}{d x} (x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x) = \frac{1}{2 x}

= 2 x + \frac{1}{2 x}

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{2}{x ^{4}}) (x + 8 x^{3}))

n = 1 \sum \infty (\frac{1}{2})^{\frac{1}{n}}

\int_{1}^{2} (x + \frac{1}{x})^{2} d x

\frac{\partial}{\partial y} (5 x^{2} - 3 x y + x yz)

x \to \infty lim (- 2 \cdot x)

What is the derivative of x^2+sqrt(x) ?
The derivative of x^2+sqrt(x) is 2x+1/(2sqrt(x))
What is the first derivative of x^2+sqrt(x) ?
The first derivative of x^2+sqrt(x) is 2x+1/(2sqrt(x))