What is the derivative of 3x^5+8x^2 ?

The derivative of 3x^5+8x^2 is 15x^4+16x

What is the first derivative of 3x^5+8x^2 ?

The first derivative of 3x^5+8x^2 is 15x^4+16x

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\frac{d}{d x} (3 x^{5} + 8 x^{2})

15 x^{4} + 16 x

Solution steps

\frac{d}{d x} (3 x^{5} + 8 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{5}) + \frac{d}{d x} (8 x^{2})

\frac{d}{d x} (3 x^{5}) = 15 x^{4}

\frac{d}{d x} (8 x^{2}) = 16 x

= 15 x^{4} + 16 x

y = e^{- x}, x = 2, y = 1

\frac{d}{d x} (arccos (\frac{x}{π}))

\int sec^{2} (x) - 6 d x

\frac{\partial}{\partial y} (3 x^{2} y^{4} + 1)

\frac{\partial}{\partial x} (4 x^{3} y^{2} - 4 x^{2} + y^{6} + 1)

What is the derivative of 3x^5+8x^2 ?
The derivative of 3x^5+8x^2 is 15x^4+16x
What is the first derivative of 3x^5+8x^2 ?
The first derivative of 3x^5+8x^2 is 15x^4+16x