What is the integral from 0 to 1 of xcos(x) ?

The integral from 0 to 1 of xcos(x) is sin(1)+cos(1)-1

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integral from 0 to 1 of xcos(x)

\int_{0}^{1} x cos (x) d x

sin (1) + cos (1) - 1

Decimal Notation

0.38177 \dots

Solution steps

\int_{0}^{1} x cos (x) d x

Apply Integration By Parts

: [x sin (x) - \int sin (x) d x]_{0}^{1}

= [x sin (x) - \int sin (x) d x]_{0}^{1}

\int sin (x) d x = - cos (x)

= [x sin (x) - (- cos (x))]_{0}^{1}

Simplify

= [x sin (x) + cos (x)]_{0}^{1}

Compute the boundaries:

sin (1) + cos (1) - 1

= sin (1) + cos (1) - 1

\int_{2}^{6} x^{2} d x

\frac{\partial}{\partial y} (3 x^{2} - 3 y^{2})

\frac{\partial}{\partial x} (9 - 2 x^{2} - y^{2})

\int \frac{1}{4} sin (2 x) d x

\int x^{3} x^{4} + 11 d x

What is the integral from 0 to 1 of xcos(x) ?
The integral from 0 to 1 of xcos(x) is sin(1)+cos(1)-1