What is the first derivative of e^r ?

The first derivative of e^r is e^r

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derivative of e^r

derivative of

e^{r}

e^{r}

Solution steps

\frac{d}{d r} (e^{r})

Apply the common derivative:

\frac{d}{d r} (e^{r}) = e^{r}

= e^{r}

\int_{0}^{\frac{3 π}{2}} 3 ∣ sin (x) ∣ d x

(y^{3} - t^{3}) d t - t y^{2} d y = 0, y (1) = 3

f (x) = \frac{5 - 4 x ^{2} + x ^{5}}{x ^{3}}

\frac{d y}{d x} = 8 x 25 - y^{2}

n = 1 \sum \infty 3 - \frac{2}{3 ^{n}}