What is the integral from b to 2b of x^7 ?

The integral from b to 2b of x^7 is 32b^8-(b^8)/8

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integral from b to 2b of x^7

\int_{b}^{2 b} x^{7} d x

32 b^{8} - \frac{b ^{8}}{8}

Solution steps

\int_{b}^{2 b} x^{7} d x

Apply the Power Rule

: [\frac{x ^{8}}{8}]_{b}^{2 b}

= [\frac{x ^{8}}{8}]_{b}^{2 b}

Compute the boundaries:

32 b^{8} - \frac{b ^{8}}{8}

= 32 b^{8} - \frac{b ^{8}}{8}

h \to + 0 lim (h)

\int 2 x y^{2} - 3 d x

\int \frac{1}{x ^{2} x ^{2} - 8} d x

\frac{\partial}{\partial y} (ln (x^{2} + 3 x y))

f (x) = x^{2} e^{x}

What is the integral from b to 2b of x^7 ?
The integral from b to 2b of x^7 is 32b^8-(b^8)/8