What is the derivative of x^2+2x-3 ?

The derivative of x^2+2x-3 is 2x+2

What is the first derivative of x^2+2x-3 ?

The first derivative of x^2+2x-3 is 2x+2

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derivative of

x^{2} + 2 x - 3

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= 2 x + 2 - 0

Simplify

= 2 x + 2

x^{2} y^{^{'}} = 2 x^{2} e^{4 x} - 3 x y

\frac{d}{d t} (\frac{cos ( t ) + sin ( t )}{- sin ( t ) + cos ( t )})

\int \frac{26}{x + x x} d x

x \to 0 lim ((x + 2)^{2})

x^{4} - 25 x^{2} + 144

What is the derivative of x^2+2x-3 ?
The derivative of x^2+2x-3 is 2x+2
What is the first derivative of x^2+2x-3 ?
The first derivative of x^2+2x-3 is 2x+2