What is the derivative of 9e^x+4/(\sqrt[3]{x)} ?

The derivative of 9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}

What is the first derivative of 9e^x+4/(\sqrt[3]{x)} ?

The first derivative of 9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}

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derivative of

9 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (9 e^{x}) = 9 e^{x}

= 9 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

\frac{\partial}{\partial x} (x^{2} y e^{x^{2} + y^{2}})

\int \frac{x - 1}{x ^{5}} d x

\int \frac{x ^{2}}{x ^{2} - 6 x + 13} d x

(1 + x^{4}) d y = - x (1 + 4 y^{2}) d x

x \to 0 lim (\frac{1}{x} \cdot sin (x))

What is the derivative of 9e^x+4/(\sqrt[3]{x)} ?
The derivative of 9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}
What is the first derivative of 9e^x+4/(\sqrt[3]{x)} ?
The first derivative of 9e^x+4/(\sqrt[3]{x)} is 9e^x-4/(3x^{4/3)}