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Popular >

y^'=xy^2-y/x

Solution

y^{^{'}} = x y^{2} - \frac{y}{x}

Solution

y = \frac{1}{x ( - x + c _{1} )}

Solution steps

y^{'} (x) = x y^{2} - \frac{y}{x}

Solve Bernoulli ODE:

y = \frac{1}{x ( - x + c _{1} )}

y = \frac{1}{x ( - x + c _{1} )}

Popular Examples

y^'=(64xy)^{1/3}

y^{^{'}} = (64 x y)^{\frac{1}{3}}

integral from 1 to infinity of 1/(y^2)

\int_{1}^{\infty} \frac{1}{y ^{2}} d y

derivative of y= x/2 derivative of

y = \frac{x}{2}

derivative of 9/(x^3)derivative of

\frac{9}{x ^{3}}

integral of ((3x^2+7x+3))/(x(x+1)^2)

\int \frac{( 3 x ^{2} + 7 x + 3 )}{x ( x + 1 ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy^2-y/x ?
The solution for y^'=xy^2-y/x is y= 1/(x(-x+c_{1))}