What is the integral from 1 to e of 2/x ?

The integral from 1 to e of 2/x is 2

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integral from 1 to e of 2/x

\int_{1}^{e} \frac{2}{x} d x

2

Solution steps

\int_{1}^{e} \frac{2}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{e} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 2 [ln ∣ x ∣]_{1}^{e}

Compute the boundaries:

1

= 2 \cdot 1

Simplify

= 2

\int (- 1)^{n}

\frac{\partial}{\partial x} (tan (x^{2} + y^{2}))

f (x) = - 8 sin (4 x) - 0.4 e^{- 0.2 x}

x \to - 9 lim (\frac{8}{x + 9})

\frac{\partial}{\partial y} (x y + 2 x - ln (x^{2} y))