What is the solution for y^'=-(4t)/y ?

The solution for y^'=-(4t)/y is y=sqrt(-4t^2+c_{1)},y=-sqrt(-4t^2+c_{1)}

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y^'=-(4t)/y

y^{^{'}} = - \frac{4 t}{y}

y = - 4 t^{2} + c_{1}, y = - - 4 t^{2} + c_{1}

Solution steps

y^{'} (t) = - \frac{4 t}{y}

Solve separable ODE:

y = - 4 t^{2} + c_{1}, y = - - 4 t^{2} + c_{1}

y = - 4 t^{2} + c_{1}, y = - - 4 t^{2} + c_{1}

x \to - 1 lim (\frac{x ^{2} - 5}{1 - x})

\frac{d}{d x} (arctan (x - x^{2} + 1))

\int (1 + sin (x))^{2} d x

(x^{2} + y^{2} + x) d x + x y d y = 0

\int \frac{y}{y ^{3} - 1} d y

What is the solution for y^'=-(4t)/y ?
The solution for y^'=-(4t)/y is y=sqrt(-4t^2+c_{1)},y=-sqrt(-4t^2+c_{1)}