What is the solution for x(dy)/(dx)+2y=-2sin(x) ?

The solution for x(dy)/(dx)+2y=-2sin(x) is y=-(2(-xcos(x)+sin(x)))/(x^2)+(c_{1})/(x^2)

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x(dy)/(dx)+2y=-2sin(x)

x \frac{d y}{d x} + 2 y = - 2 sin (x)

y = - \frac{2 ( - x cos ( x ) + sin ( x ) )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

Solution steps

x \frac{d y}{d x} + 2 y = - 2 sin (x)

Solve linear ODE:

y = - \frac{2 ( - x cos ( x ) + sin ( x ) )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

y = - \frac{2 ( - x cos ( x ) + sin ( x ) )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

\int_{0}^{4} (5 x - x^{2}) - x d x

f (x) = 2 x^{2} e^{x}

\frac{d ^{2}}{d x ^{2}} (\frac{1}{1 + x})

h \to 0 lim (\frac{1}{3 h})

\frac{d}{d x} (\frac{cos ( x )}{e ^{2 x}} - 2)

What is the solution for x(dy)/(dx)+2y=-2sin(x) ?
The solution for x(dy)/(dx)+2y=-2sin(x) is y=-(2(-xcos(x)+sin(x)))/(x^2)+(c_{1})/(x^2)