What is the derivative of y= 8/(sqrt(x-7)) ?

The derivative of y= 8/(sqrt(x-7)) is -4/((x-7)^{3/2)}

What is the first derivative of y= 8/(sqrt(x-7)) ?

The first derivative of y= 8/(sqrt(x-7)) is -4/((x-7)^{3/2)}

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derivative of

y = \frac{8}{x - 7}

- \frac{4}{( x - 7 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{8}{x - 7})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{1}{x - 7})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d x} ((x - 7)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x - 7 ) ^{\frac{3}{2}}} \frac{d}{d x} (x - 7)

= - \frac{1}{2 ( x - 7 ) ^{\frac{3}{2}}} \frac{d}{d x} (x - 7)

\frac{d}{d x} (x - 7) = 1

= 8 (- \frac{1}{2 ( x - 7 ) ^{\frac{3}{2}}} \cdot 1)

Simplify

8 (- \frac{1}{2 ( x - 7 ) ^{\frac{3}{2}}} \cdot 1) : - \frac{4}{( x - 7 ) ^{\frac{3}{2}}}

= - \frac{4}{( x - 7 ) ^{\frac{3}{2}}}

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What is the derivative of y= 8/(sqrt(x-7)) ?
The derivative of y= 8/(sqrt(x-7)) is -4/((x-7)^{3/2)}
What is the first derivative of y= 8/(sqrt(x-7)) ?
The first derivative of y= 8/(sqrt(x-7)) is -4/((x-7)^{3/2)}