What is the d/(dt)(sec^2(t)) ?

The d/(dt)(sec^2(t)) is 2sec^2(t)tan(t)

What is the first d/(dt)(sec^2(t)) ?

The first d/(dt)(sec^2(t)) is 2sec^2(t)tan(t)

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\frac{d}{d t} (sec^{2} (t))

2 sec^{2} (t) tan (t)

Solution steps

\frac{d}{d t} (sec^{2} (t))

Apply the chain rule:

2 sec (t) \frac{d}{d t} (sec (t))

= 2 sec (t) \frac{d}{d t} (sec (t))

\frac{d}{d t} (sec (t)) = sec (t) tan (t)

= 2 sec (t) sec (t) tan (t)

Simplify

2 sec (t) sec (t) tan (t) : 2 sec^{2} (t) tan (t)

= 2 sec^{2} (t) tan (t)

\frac{x ^{2} - 100}{x + 10}

(6 a + 1)^{2}

\frac{d}{d x} (10 (3 x + 1) (1 - 5 x))

\frac{\partial}{\partial x} (\frac{3 x}{x ^{2} + y ^{2}})

\frac{d}{d x} (4 sec (x) - 7 x)

What is the d/(dt)(sec^2(t)) ?
The d/(dt)(sec^2(t)) is 2sec^2(t)tan(t)
What is the first d/(dt)(sec^2(t)) ?
The first d/(dt)(sec^2(t)) is 2sec^2(t)tan(t)