What is the limit as x approaches+0 of 1/(sqrt(x)) ?

The limit as x approaches+0 of 1/(sqrt(x)) is diverges

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limit as x approaches+0 of 1/(sqrt(x))

x \to + 0 lim (\frac{1}{x})

diverges

Solution steps

x \to 0 lim (\frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x}) = \infty

x \to 0 - lim (\frac{1}{x}) =

Undefined

= diverges

x^{^{''}} + k x^{^{'}} + x = 0

\frac{d}{d x} (\frac{3 x ^{2}}{4})

x \to 0 + lim (cot (4 x))

n = 1 \sum \infty \frac{1}{n ^{2} + n + 1}

10 (2 e^{x^{2}} x^{2} + e^{x^{2}})

What is the limit as x approaches+0 of 1/(sqrt(x)) ?
The limit as x approaches+0 of 1/(sqrt(x)) is diverges