What is the derivative of (x^3+5e^x) ?

The derivative of (x^3+5e^x) is 3x^2e^x+e^x(x^3+5)

What is the first derivative of (x^3+5e^x) ?

The first derivative of (x^3+5e^x) is 3x^2e^x+e^x(x^3+5)

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\frac{d}{d x} ((x^{3} + 5) e^{x})

3 x^{2} e^{x} + e^{x} (x^{3} + 5)

Solution steps

\frac{d}{d x} ((x^{3} + 5) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3} + 5, g = e^{x}

= \frac{d}{d x} (x^{3} + 5) e^{x} + \frac{d}{d x} (e^{x}) (x^{3} + 5)

\frac{d}{d x} (x^{3} + 5) = 3 x^{2}

\frac{d}{d x} (e^{x}) = e^{x}

= 3 x^{2} e^{x} + e^{x} (x^{3} + 5)

\int cos (4 x) 2 - sin (4 x) d x

\int \frac{1}{( 9 - x ^{2} )} d x

\frac{d}{d x} (4 (x + 4)^{3})

f (x) = x^{2} - 3 x - 2, at x = 2

\frac{d}{d x} (- \frac{b}{x ^{2}})

What is the derivative of (x^3+5e^x) ?
The derivative of (x^3+5e^x) is 3x^2e^x+e^x(x^3+5)
What is the first derivative of (x^3+5e^x) ?
The first derivative of (x^3+5e^x) is 3x^2e^x+e^x(x^3+5)