What is the solution for (dy)/(dx)=(cos(7x))/(e^{7y)},y(0)=0 ?

The solution for (dy)/(dx)=(cos(7x))/(e^{7y)},y(0)=0 is y=(ln(sin(7x)+1))/7

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(dy)/(dx)=(cos(7x))/(e^{7y)},y(0)=0

\frac{d y}{d x} = \frac{cos ( 7 x )}{e ^{7 y}}, y (0) = 0

y = \frac{ln ( sin ( 7 x ) + 1 )}{7}

Solution steps

\frac{d y}{d x} = \frac{cos ( 7 x )}{e ^{7 y}}

Solve separable ODE:

y = \frac{ln ( sin ( 7 x ) + 1 )}{7}

y = \frac{ln ( sin ( 7 x ) + 1 )}{7}

x \to 1 + lim (x^{2} - 2)

y^{^{''}} - 6 y + 13 y = 0

n = 1 \sum \infty 2 n - 1

\int \frac{2 x ^{3} - 4 x - 8}{( x ^{2} - x ) ( x ^{2} + 4 )} d x

0.0588 (80)^{1.125}

What is the solution for (dy)/(dx)=(cos(7x))/(e^{7y)},y(0)=0 ?
The solution for (dy)/(dx)=(cos(7x))/(e^{7y)},y(0)=0 is y=(ln(sin(7x)+1))/7