What is the derivative of (xlog_{2}(x))^2 ?

The derivative of (xlog_{2}(x))^2 is 2xlog_{2}(x)^2+(2xlog_{2}(x))/(ln(2))

What is the first derivative of (xlog_{2}(x))^2 ?

The first derivative of (xlog_{2}(x))^2 is 2xlog_{2}(x)^2+(2xlog_{2}(x))/(ln(2))

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derivative of

(x lo g_{2} (x))^{2}

2 x lo g_{2} (x)^{2} + \frac{2 x lo g _{2} ( x )}{ln ( 2 )}

Solution steps

\frac{d}{d x} ((x lo g_{2} (x))^{2})

Simplify

(x lo g_{2} (x))^{2} : x^{2} lo g_{2} (x)^{2}

= \frac{d}{d x} (x^{2} lo g_{2} (x)^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = lo g_{2} (x)^{2}

= \frac{d}{d x} (x^{2}) lo g_{2} (x)^{2} + \frac{d}{d x} (lo g_{2} (x)^{2}) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (lo g_{2} (x)^{2}) = \frac{2 lo g _{2} ( x )}{ln ( 2 ) x}

= 2 x lo g_{2} (x)^{2} + \frac{2 lo g _{2} ( x )}{ln ( 2 ) x} x^{2}

\frac{2 lo g _{2} ( x )}{ln ( 2 ) x} x^{2} = \frac{2 x lo g _{2} ( x )}{ln ( 2 )}

= 2 x lo g_{2} (x)^{2} + \frac{2 x lo g _{2} ( x )}{ln ( 2 )}

\int \frac{lo g _{10} ( x )}{x} d x

\frac{d}{d t} (e^{t^{2} - t})

arctan (\frac{x}{2})

2 y^{^{''}} + 50 y = 0

\int 1 - \frac{2 x}{x ^{2} + 1} d x

What is the derivative of (xlog_{2}(x))^2 ?
The derivative of (xlog_{2}(x))^2 is 2xlog_{2}(x)^2+(2xlog_{2}(x))/(ln(2))
What is the first derivative of (xlog_{2}(x))^2 ?
The first derivative of (xlog_{2}(x))^2 is 2xlog_{2}(x)^2+(2xlog_{2}(x))/(ln(2))