What is the tangent of f(x)=12sqrt(x),(9,36) ?

The tangent of f(x)=12sqrt(x),(9,36) is y=2x+18

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tangent of f(x)=12sqrt(x),(9,36)

tangent of

f (x) = 12 x, (9, 36)

y = 2 x + 18

Solution steps

Find the slope of

f (x) = 12 x : \frac{df ( x )}{d x} = \frac{6}{x}

Compute the slope of

f (x) = 12 x

(9, 36) : m = 2

Find the line with slope m=

2

and passing through

(9, 36) : y = 2 x + 18

y = 2 x + 18

n = 0 \sum \infty \frac{1}{2} \cdot (- 1)^{n}

\frac{\partial}{\partial x} (- 4 x y - x^{4} - y^{4})

f (x) = x + 4

\int \frac{x ^{2} - x + 14}{x ^{3} + 7 x} d x

What is the tangent of f(x)=12sqrt(x),(9,36) ?
The tangent of f(x)=12sqrt(x),(9,36) is y=2x+18