What is the solution for (dy)/(dx)=e^{2x-y} ?

The solution for (dy)/(dx)=e^{2x-y} is y=ln(1/2 e^{2x}+c_{1})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=e^{2x-y}

\frac{d y}{d x} = e^{2 x - y}

y = ln (\frac{1}{2} e^{2 x} + c_{1})

Solution steps

\frac{d y}{d x} = e^{2 x - y}

Solve separable ODE:

y = ln (\frac{1}{2} e^{2 x} + c_{1})

y = ln (\frac{1}{2} e^{2 x} + c_{1})

\int - e^{- x} ln (x) d x

(1 + x^{2}) (e^{2 t} d t - e^{x} d x) - (1 + x) d x = 0

\frac{s e ^{- 2 s}}{s ^{2} + 16}

\int_{0}^{1} cos^{2} (π x) d x

\int \frac{2 - x}{x ^{2}} d x

What is the solution for (dy)/(dx)=e^{2x-y} ?
The solution for (dy)/(dx)=e^{2x-y} is y=ln(1/2 e^{2x}+c_{1})