What is the integral from-3 to-1 of (x+2)^{99} ?

The integral from-3 to-1 of (x+2)^{99} is 0

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integral from-3 to-1 of (x+2)^{99}

\int_{- 3}^{- 1} (x + 2)^{99} d x

0

Solution steps

\int_{- 3}^{- 1} (x + 2)^{99} d x

Apply u-substitution

: \int_{- 1}^{1} u^{99} d u

= \int_{- 1}^{1} u^{99} d u

Apply the Power Rule

: [\frac{u ^{100}}{100}]_{- 1}^{1}

= [\frac{u ^{100}}{100}]_{- 1}^{1}

Compute the boundaries:

0

= 0

7 x - \frac{9}{x ^{6}}

f (x) = x e^{- \frac{x}{2}}, at x = \frac{1}{2}

\int \frac{x ^{3}}{x ^{4} - 1} d x

t^{2} y^{^{''}} + 2 t y^{^{'}} - 30 y = 0

x \to 3 lim (\frac{( x + 3 )}{x - 3})

What is the integral from-3 to-1 of (x+2)^{99} ?
The integral from-3 to-1 of (x+2)^{99} is 0