What is area f(x)= 1/(x^2),[2,6] ?

The answer to area f(x)= 1/(x^2),[2,6] is 1/3

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area f(x)= 1/(x^2),[2,6]

area

f (x) = \frac{1}{x ^{2}}, [2, 6]

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

Apply the area formula:

\int_{2}^{6} \frac{1}{∣ x ∣ ^{2}} d x

Solve

\int_{2}^{6} \frac{1}{∣ x ∣ ^{2}} d x : \frac{1}{3}

The area is:

= \frac{1}{3}

(ln (x))^{4}

\int 2 + e^{2 x} + e^{- 2 x} d x

\frac{\partial}{\partial y} (x^{3} - y^{3} + 2 x y)

cos (t) \cdot cos (π)

\int sin^{5} (3 x) cos (3 x) d x

What is area f(x)= 1/(x^2),[2,6] ?
The answer to area f(x)= 1/(x^2),[2,6] is 1/3