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Popular >

derivative of f(t)=sqrt(3t^2-t)

Solution

derivative of

f (t) = 3 t^{2} - t

Solution

\frac{6 t - 1}{2 3 t ^{2} - t}

Solution steps

\frac{d}{d t} (3 t^{2} - t)

Apply the chain rule:

\frac{1}{2 3 t ^{2} - t} \frac{d}{d t} (3 t^{2} - t)

= \frac{1}{2 3 t ^{2} - t} \frac{d}{d t} (3 t^{2} - t)

\frac{d}{d t} (3 t^{2} - t) = 6 t - 1

= \frac{1}{2 3 t ^{2} - t} (6 t - 1)

Simplify

\frac{1}{2 3 t ^{2} - t} (6 t - 1) : \frac{6 t - 1}{2 3 t ^{2} - t}

= \frac{6 t - 1}{2 3 t ^{2} - t}

Popular Examples

integral of (2x^2+x+1)/(x^3+2x^2+x)

\int \frac{2 x ^{2} + x + 1}{x ^{3} + 2 x ^{2} + x} d x

derivative of sqrt(x^2+2x)

\frac{d}{d x} (x^{2} + 2 x)

derivative of y=((x^2+1)/(x^2-1))^6 derivative of

y = (\frac{x ^{2} + 1}{x ^{2} - 1})^{6}

derivative of cos(3xcos(2x))

\frac{d}{d x} (cos (3 x) cos (2 x))

tangent of f(x)=sqrt(7-6x),\at x=-1 tangent of

f (x) = 7 - 6 x, at x = - 1

Frequently Asked Questions (FAQ)

What is the derivative of f(t)=sqrt(3t^2-t) ?
The derivative of f(t)=sqrt(3t^2-t) is (6t-1)/(2sqrt(3t^2-t))
What is the first derivative of f(t)=sqrt(3t^2-t) ?
The first derivative of f(t)=sqrt(3t^2-t) is (6t-1)/(2sqrt(3t^2-t))