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Popular >

derivative of 28+(12.4)t-(0.045)t^3

Solution

derivative of

28 + (12.4) t - (0.045) t^{3}

Solution

- 0.135 t^{2} + 12.4

Solution steps

\frac{d}{d t} (28 + 12.4 t - 0.045 t^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (28) + \frac{d}{d t} (12.4 t) - \frac{d}{d t} (0.045 t^{3})

\frac{d}{d t} (28) = 0

\frac{d}{d t} (12.4 t) = 12.4

\frac{d}{d t} (0.045 t^{3}) = 0.135 t^{2}

= 0 + 12.4 - 0.135 t^{2}

Simplify

= - 0.135 t^{2} + 12.4

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Frequently Asked Questions (FAQ)

What is the derivative of 28+(12.4)t-(0.045)t^3 ?
The derivative of 28+(12.4)t-(0.045)t^3 is -0.135t^2+12.4
What is the first derivative of 28+(12.4)t-(0.045)t^3 ?
The first derivative of 28+(12.4)t-(0.045)t^3 is -0.135t^2+12.4