What is the derivative of 1-x+ln(x) ?

The derivative of 1-x+ln(x) is 1/x-1

What is the first derivative of 1-x+ln(x) ?

The first derivative of 1-x+ln(x) is 1/x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (1 - x + ln (x))

\frac{1}{x} - 1

Solution steps

\frac{d}{d x} (1 - x + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d x}{d x} + \frac{d}{d x} (ln (x))

\frac{d}{d x} (1) = 0

\frac{d x}{d x} = 1

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 0 - 1 + \frac{1}{x}

Simplify

= \frac{1}{x} - 1

\int_{0}^{a} e^{\frac{x}{a}} - e^{- \frac{x}{a}} d x

x = 6.4 sin (1. 2^{2} t^{2})

\frac{d}{d x} (ln (\frac{x}{5}))

\int 10 x ln (x + 2) d x

What is the derivative of 1-x+ln(x) ?
The derivative of 1-x+ln(x) is 1/x-1
What is the first derivative of 1-x+ln(x) ?
The first derivative of 1-x+ln(x) is 1/x-1