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Popular >

y^'=x+y,y(0)=10

Solution

y^{^{'}} = x + y, y (0) = 10

Solution

y = - x - 1 + 11 e^{x}

Solution steps

y^{'} (x) = x + y

Solve linear ODE:

y = - x - 1 + 11 e^{x}

y = - x - 1 + 11 e^{x}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=x+y,y(0)=10 ?
The solution for y^'=x+y,y(0)=10 is y=-x-1+11e^x