What is (\partial)/(\partial y)(x^2+2y^2) ?

The answer to (\partial)/(\partial y)(x^2+2y^2) is 4y

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(\partial)/(\partial y)(x^2+2y^2)

\frac{\partial}{\partial y} (x^{2} + 2 y^{2})

4 y

Solution steps

\frac{\partial}{\partial y} (x^{2} + 2 y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) + \frac{\partial}{\partial y} (2 y^{2})

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (2 y^{2}) = 4 y

= 0 + 4 y

Simplify

= 4 y

\frac{d}{d x} (arctan (\frac{1 - x}{1 + x}))

\int_{0}^{3} (- x^{2} + x - 1) d x

\int_{1}^{16} \frac{1}{x} d x

\int \frac{2 x}{3 ( x ^{2} + 1 )} d x

\frac{d}{d x} (x^{12} ln (x))

What is (\partial)/(\partial y)(x^2+2y^2) ?
The answer to (\partial)/(\partial y)(x^2+2y^2) is 4y