What is (\partial)/(\partial x)(x^2y-y^2-7) ?

The answer to (\partial)/(\partial x)(x^2y-y^2-7) is 2xy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2y-y^2-7)

\frac{\partial}{\partial x} (x^{2} y - y^{2} - 7)

2 x y

Solution steps

\frac{\partial}{\partial x} (x^{2} y - y^{2} - 7)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2} y) - \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (7)

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (7) = 0

= 2 y x - 0 - 0

Simplify

= 2 x y

\int sec^{5} (4 x) tan (4 x) d x

x \to - 1 lim (10 x)

x y + 5 e^{y} = 5 e

\frac{d}{d x} (tan (a x + b))

\frac{\partial}{\partial x} (3 y^{2} x - y^{3} - x^{4})

What is (\partial)/(\partial x)(x^2y-y^2-7) ?
The answer to (\partial)/(\partial x)(x^2y-y^2-7) is 2xy