What is area f(x)=x^2-1,g(x)=-x+2,0,1 ?

The answer to area f(x)=x^2-1,g(x)=-x+2,0,1 is 13/6

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area f(x)=x^2-1,g(x)=-x+2,0,1

area

f (x) = x^{2} - 1, g (x) = - x + 2, 0, 1

\frac{13}{6}

Decimal Notation

2.16666 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} x^{2} - 1 - (- x + 2) d x

Solve

\int_{0}^{1} x^{2} - 1 - (- x + 2) d x : \frac{13}{6}

The area is:

= \frac{13}{6}

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What is area f(x)=x^2-1,g(x)=-x+2,0,1 ?
The answer to area f(x)=x^2-1,g(x)=-x+2,0,1 is 13/6