What is the integral of (\sqrt[3]{x}+\sqrt[4]{x}) ?

The integral of (\sqrt[3]{x}+\sqrt[4]{x}) is 3/4 x^{4/3}+4/5 x^{5/4}+C

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integral of (\sqrt[3]{x}+\sqrt[4]{x})

\frac{3}{4} x^{\frac{4}{3}} + \frac{4}{5} x^{\frac{5}{4}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{3}{4} x^{\frac{4}{3}} + \frac{4}{5} x^{\frac{5}{4}}

Add a constant to the solution

= \frac{3}{4} x^{\frac{4}{3}} + \frac{4}{5} x^{\frac{5}{4}} + C

y = - x^{2} + 62

\frac{d}{d x} (\frac{cos ( x )}{cos ( x ) + 1})

\frac{x ^{2} + x + 1}{2 x}

\int \frac{8 x}{8 x + 3} d x

\frac{d}{d x} ((7 - 3 x^{3})^{2})

What is the integral of (\sqrt[3]{x}+\sqrt[4]{x}) ?
The integral of (\sqrt[3]{x}+\sqrt[4]{x}) is 3/4 x^{4/3}+4/5 x^{5/4}+C