What is the integral from 0 to 2 of xe^{-x} ?

The integral from 0 to 2 of xe^{-x} is -3/(e^2)+1

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integral from 0 to 2 of xe^{-x}

\int_{0}^{2} x e^{- x} d x

- \frac{3}{e ^{2}} + 1

Decimal Notation

0.59399 \dots

Solution steps

\int_{0}^{2} x e^{- x} d x

Apply Integration By Parts

: [- e^{- x} x - \int - e^{- x} d x]_{0}^{2}

= [- e^{- x} x - \int - e^{- x} d x]_{0}^{2}

\int - e^{- x} d x = e^{- x}

= [- e^{- x} x - e^{- x}]_{0}^{2}

Compute the boundaries:

- \frac{3}{e ^{2}} + 1

= - \frac{3}{e ^{2}} + 1

x \to 0 lim ((x - 2) e^{- \frac{1}{x}})

x (\frac{d y}{d x}) = 2 x + 2 y

\int \frac{1}{1 + 29 x} d x

x \to 0 lim (- \frac{3}{x})

- \frac{20 , 0}{1 + 0.2 t} + 21, 0

What is the integral from 0 to 2 of xe^{-x} ?
The integral from 0 to 2 of xe^{-x} is -3/(e^2)+1