What is the integral from 0 to 1 of xsqrt(1-x^2) ?

The integral from 0 to 1 of xsqrt(1-x^2) is 1/3

Popular >

integral from 0 to 1 of xsqrt(1-x^2)

\int_{0}^{1} x 1 - x^{2} d x

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

\int_{0}^{1} x 1 - x^{2} d x

Apply u-substitution

: \int_{1}^{0} - u^{2} d u

= \int_{1}^{0} - u^{2} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{1} - u^{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{0}^{1} u^{2} d u)

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{0}^{1}

= - (- [\frac{u ^{3}}{3}]_{0}^{1})

Simplify

= [\frac{u ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= \frac{1}{3}

\int \frac{2 u - 1}{- u + 2} d u

\frac{d}{d x} (\frac{( x + 1 ) ^{2}}{x + 3})

\frac{d}{d x} (e^{\frac{1}{3} x})

e^{- x} - e^{- x} x

\frac{d}{d x} (e^{x - 4})

What is the integral from 0 to 1 of xsqrt(1-x^2) ?
The integral from 0 to 1 of xsqrt(1-x^2) is 1/3