What is the solution for (dy)/(dx)=(1+y^2)tan(x),y(0)=1 ?

The solution for (dy)/(dx)=(1+y^2)tan(x),y(0)=1 is y=tan(-ln(cos(x))+pi/4)

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(dy)/(dx)=(1+y^2)tan(x),y(0)=1

\frac{d y}{d x} = (1 + y^{2}) tan (x), y (0) = 1

y = tan (- ln (cos (x)) + \frac{π}{4})

Solution steps

\frac{d y}{d x} = (1 + y^{2}) tan (x)

Solve separable ODE:

y = tan (- ln (cos (x)) + \frac{π}{4})

y = tan (- ln (cos (x)) + \frac{π}{4})

x \to 1 lim (2 x)

f (x) = x^{2} - 2 x, (5, 9)

x \to 0 lim (\frac{1 + x - 1}{x})

\int_{0}^{3} c \cdot (3 - x) d x

(1, - 2), (3, 4)

What is the solution for (dy)/(dx)=(1+y^2)tan(x),y(0)=1 ?
The solution for (dy)/(dx)=(1+y^2)tan(x),y(0)=1 is y=tan(-ln(cos(x))+pi/4)