What is the tangent of y=5x^4+3x-6,(1,2) ?

The tangent of y=5x^4+3x-6,(1,2) is y=23x-21

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tangent of y=5x^4+3x-6,(1,2)

tangent of

y = 5 x^{4} + 3 x - 6, (1, 2)

y = 23 x - 21

Solution steps

Find the slope of

y = 5 x^{4} + 3 x - 6 : \frac{d y}{d x} = 20 x^{3} + 3

Compute the slope of

y = 5 x^{4} + 3 x - 6

(1, 2) : m = 23

Find the line with slope m=

23

and passing through

(1, 2) : y = 23 x - 21

y = 23 x - 21

\frac{\partial}{\partial y} (\frac{5 x y}{10 x - y})

\int_{- 8}^{8} (64 - x^{2}) d x

\frac{2}{( s + 3 )}

\frac{d}{d x} (\frac{1}{sin ( 3 x )})

\frac{d}{d x} (\frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}})

What is the tangent of y=5x^4+3x-6,(1,2) ?
The tangent of y=5x^4+3x-6,(1,2) is y=23x-21