What is the tangent of f(x)=6e^x+x,(0,6) ?

The tangent of f(x)=6e^x+x,(0,6) is y=7x+6

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tangent of f(x)=6e^x+x,(0,6)

tangent of

f (x) = 6 e^{x} + x, (0, 6)

y = 7 x + 6

Solution steps

Find the slope of

f (x) = 6 e^{x} + x : \frac{df ( x )}{d x} = 6 e^{x} + 1

Compute the slope of

f (x) = 6 e^{x} + x

(0, 6) : m = 7

Find the line with slope m=

7

and passing through

(0, 6) : y = 7 x + 6

y = 7 x + 6

\frac{d}{d x} (cos^{4} (2 x^{3} - 5))

\int \frac{5 - 2 x ^{2}}{y ^{2}} d y

\int sin (10 x) d x

y = x (x + 3) (x - 4), x = 0

(5 e^{x})^{^{'}}

What is the tangent of f(x)=6e^x+x,(0,6) ?
The tangent of f(x)=6e^x+x,(0,6) is y=7x+6