What is the integral from b to 2b of x^8 ?

The integral from b to 2b of x^8 is (511b^9)/9

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integral from b to 2b of x^8

\int_{b}^{2 b} x^{8} d x

\frac{511 b ^{9}}{9}

Solution steps

\int_{b}^{2 b} x^{8} d x

Apply the Power Rule

: [\frac{x ^{9}}{9}]_{b}^{2 b}

= [\frac{x ^{9}}{9}]_{b}^{2 b}

Compute the boundaries:

\frac{512 b ^{9}}{9} - \frac{b ^{9}}{9}

= \frac{512 b ^{9}}{9} - \frac{b ^{9}}{9}

Simplify

= \frac{511 b ^{9}}{9}

\frac{d}{d x} (sec^{2} (x) - 2)

\int x (x - 2)^{4} d x

n = 1 \sum \infty \frac{1}{n ^{2} + 300}

y^{^{'}} = 2 y (5 - y)

f (x) = (x^{2} - 2) (x^{3} - 3 x), at x = - 2

What is the integral from b to 2b of x^8 ?
The integral from b to 2b of x^8 is (511b^9)/9