What is the derivative of 7/(sqrt(x+4)) ?

The derivative of 7/(sqrt(x+4)) is -7/(2(x+4)^{3/2)}

What is the first derivative of 7/(sqrt(x+4)) ?

The first derivative of 7/(sqrt(x+4)) is -7/(2(x+4)^{3/2)}

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derivative of

\frac{7}{x + 4}

- \frac{7}{2 ( x + 4 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{7}{x + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{x + 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} ((x + 4)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x + 4 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 4)

= - \frac{1}{2 ( x + 4 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 4)

\frac{d}{d x} (x + 4) = 1

= 7 (- \frac{1}{2 ( x + 4 ) ^{\frac{3}{2}}} \cdot 1)

Simplify

7 (- \frac{1}{2 ( x + 4 ) ^{\frac{3}{2}}} \cdot 1) : - \frac{7}{2 ( x + 4 ) ^{\frac{3}{2}}}

= - \frac{7}{2 ( x + 4 ) ^{\frac{3}{2}}}

\int x^{3} e^{x^{4} + 5} d x

y + y^{4} = (y^{6} + 3 x) y^{^{'}}

cos (x) y^{^{'}} - sin (x) y = 0

\int \frac{3 - z}{- 1 + z ^{2}} d z

What is the derivative of 7/(sqrt(x+4)) ?
The derivative of 7/(sqrt(x+4)) is -7/(2(x+4)^{3/2)}
What is the first derivative of 7/(sqrt(x+4)) ?
The first derivative of 7/(sqrt(x+4)) is -7/(2(x+4)^{3/2)}