What is the solution for x^2y^{''}-2y=0,y(1)=0,y^'(1)=3 ?

The solution for x^2y^{''}-2y=0,y(1)=0,y^'(1)=3 is y=x^2-1/x

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x^2y^{''}-2y=0,y(1)=0,y^'(1)=3

x^{2} y^{^{''}} - 2 y = 0, y (1) = 0, y^{^{'}} (1) = 3

y = x^{2} - \frac{1}{x}

Solution steps

x^{2} y^{''} (x) - 2 y = 0

Solve linear ODE:

y = x^{2} - \frac{1}{x}

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What is the solution for x^2y^{''}-2y=0,y(1)=0,y^'(1)=3 ?
The solution for x^2y^{''}-2y=0,y(1)=0,y^'(1)=3 is y=x^2-1/x