What is the derivative of f(x)= 1/6 (2x+1)^3 ?

The derivative of f(x)= 1/6 (2x+1)^3 is (2x+1)^2

What is the first derivative of f(x)= 1/6 (2x+1)^3 ?

The first derivative of f(x)= 1/6 (2x+1)^3 is (2x+1)^2

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derivative of

f (x) = \frac{1}{6} (2 x + 1)^{3}

(2 x + 1)^{2}

Solution steps

\frac{d}{d x} (\frac{1}{6} (2 x + 1)^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{6} \frac{d}{d x} ((2 x + 1)^{3})

Apply the chain rule:

3 (2 x + 1)^{2} \frac{d}{d x} (2 x + 1)

= 3 (2 x + 1)^{2} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= \frac{1}{6} \cdot 3 (2 x + 1)^{2} \cdot 2

Simplify

\frac{1}{6} \cdot 3 (2 x + 1)^{2} \cdot 2 : (2 x + 1)^{2}

= (2 x + 1)^{2}

\int \frac{( x ^{5} - x ^{3} + 6 x )}{x ^{4}} d x

x^{3} - 11 x^{2} + 30 x, - x^{3} + 11 x^{2} - 30 x

f (x) = (x - 2)^{3} (x - 1)

y^{^{''}} + 36 y = - 24 sin (6 t)

(x e^{x})^{^{'}}

What is the derivative of f(x)= 1/6 (2x+1)^3 ?
The derivative of f(x)= 1/6 (2x+1)^3 is (2x+1)^2
What is the first derivative of f(x)= 1/6 (2x+1)^3 ?
The first derivative of f(x)= 1/6 (2x+1)^3 is (2x+1)^2