What is the derivative of sin(3x^2+2x^3) ?

The derivative of sin(3x^2+2x^3) is cos(3x^2)*6x+6x^2

What is the first derivative of sin(3x^2+2x^3) ?

The first derivative of sin(3x^2+2x^3) is cos(3x^2)*6x+6x^2

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\frac{d}{d x} (sin (3 x^{2}) + 2 x^{3})

cos (3 x^{2}) \cdot 6 x + 6 x^{2}

Solution steps

\frac{d}{d x} (sin (3 x^{2}) + 2 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (3 x^{2})) + \frac{d}{d x} (2 x^{3})

\frac{d}{d x} (sin (3 x^{2})) = cos (3 x^{2}) \cdot 6 x

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

= cos (3 x^{2}) \cdot 6 x + 6 x^{2}

\frac{\partial}{\partial x} (y e^{\frac{y}{x}})

\int (sin (3 x)) d x

\frac{\partial}{\partial x} (6 cos^{4} (3 x + 2))

\frac{d}{d x} (e^{2 x} + e^{- 2 x})

(x - 3)^{^{'}}

What is the derivative of sin(3x^2+2x^3) ?
The derivative of sin(3x^2+2x^3) is cos(3x^2)*6x+6x^2
What is the first derivative of sin(3x^2+2x^3) ?
The first derivative of sin(3x^2+2x^3) is cos(3x^2)*6x+6x^2