What is (\partial)/(\partial x)(cos(2y-x)) ?

The answer to (\partial)/(\partial x)(cos(2y-x)) is sin(2y-x)

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(\partial)/(\partial x)(cos(2y-x))

\frac{\partial}{\partial x} (cos (2 y - x))

sin (2 y - x)

Solution steps

\frac{\partial}{\partial x} (cos (2 y - x))

Treat

y

as a constant

Apply the chain rule:

- sin (2 y - x) \frac{\partial}{\partial x} (2 y - x)

= - sin (2 y - x) \frac{\partial}{\partial x} (2 y - x)

\frac{\partial}{\partial x} (2 y - x) = - 1

= - sin (2 y - x) (- 1)

Simplify

= sin (2 y - x)

\frac{d}{d x} (lo g_{10} (1 - 2 x^{2}))

(1 + ln (x) + \frac{y}{x}) d x = (6 - ln (x)) d y

\frac{x d y}{d x} - \frac{2 d y}{d x} - (x - 2) sin (x) + y = 0

\frac{\partial}{\partial x} (4 x e^{x})

\int_{0}^{\infty} x e^{- a x} d x

What is (\partial)/(\partial x)(cos(2y-x)) ?
The answer to (\partial)/(\partial x)(cos(2y-x)) is sin(2y-x)