What is the derivative of 2x+sin(2x) ?

The derivative of 2x+sin(2x) is 2+cos(2x)*2

What is the first derivative of 2x+sin(2x) ?

The first derivative of 2x+sin(2x) is 2+cos(2x)*2

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\frac{d}{d x} (2 x + sin (2 x))

2 + cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (2 x + sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 2 + cos (2 x) \cdot 2

\frac{\partial}{\partial y} (x e^{7 x y})

\int e^{(x - 1)} d x

\frac{d y}{d x} = y e^{- x^{2}}

\frac{\partial}{\partial x} (e^{x + y + 9})

\int e^{\frac{r}{2}} d r

What is the derivative of 2x+sin(2x) ?
The derivative of 2x+sin(2x) is 2+cos(2x)*2
What is the first derivative of 2x+sin(2x) ?
The first derivative of 2x+sin(2x) is 2+cos(2x)*2