What is the derivative of f(x)=\sqrt[4]{x} ?

The derivative of f(x)=\sqrt[4]{x} is 1/(4x^{3/4)}

What is the first derivative of f(x)=\sqrt[4]{x} ?

The first derivative of f(x)=\sqrt[4]{x} is 1/(4x^{3/4)}

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derivative of

\frac{1}{4 x ^{\frac{3}{4}}}

Solution steps

Apply radical rule:

= \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

\frac{1}{4} x^{\frac{1}{4} - 1} : \frac{1}{4 x ^{\frac{3}{4}}}

= \frac{1}{4 x ^{\frac{3}{4}}}

y = x + \frac{2}{x}

x \to 5 + lim (x - 5)

\frac{1}{( s + 3 ) ^{3}}

\frac{d}{d x} (x sin^{2} (x))

What is the derivative of f(x)=\sqrt[4]{x} ?
The derivative of f(x)=\sqrt[4]{x} is 1/(4x^{3/4)}
What is the first derivative of f(x)=\sqrt[4]{x} ?
The first derivative of f(x)=\sqrt[4]{x} is 1/(4x^{3/4)}