What is the derivative of 3-3sin(x) ?

The derivative of 3-3sin(x) is -3cos(x)

What is the first derivative of 3-3sin(x) ?

The first derivative of 3-3sin(x) is -3cos(x)

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\frac{d}{d x} (3 - 3 sin (x))

- 3 cos (x)

Solution steps

\frac{d}{d x} (3 - 3 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) - \frac{d}{d x} (3 sin (x))

\frac{d}{d x} (3) = 0

\frac{d}{d x} (3 sin (x)) = 3 cos (x)

= 0 - 3 cos (x)

Simplify

= - 3 cos (x)

\int \frac{1}{u ^{2} + 2 u} d u

\int t^{2} e^{- 21 t} d t

y^{^{'}} = 3 x y^{2}

\frac{d}{d x} (\frac{x}{3 x ^{2} + 4})

f (x) = - e^{x} x + e^{x}

What is the derivative of 3-3sin(x) ?
The derivative of 3-3sin(x) is -3cos(x)
What is the first derivative of 3-3sin(x) ?
The first derivative of 3-3sin(x) is -3cos(x)