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Popular >

2xy^'+y=6x,y(4)=22

Solution

2 x y^{^{'}} + y = 6 x, y (4) = 22

Solution

y = 2 x + \frac{28}{x}

Solution steps

2 x y^{'} (x) + y = 6 x

Solve linear ODE:

y = 2 x + \frac{28}{x}

y = 2 x + \frac{28}{x}

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Frequently Asked Questions (FAQ)

What is the solution for 2xy^'+y=6x,y(4)=22 ?
The solution for 2xy^'+y=6x,y(4)=22 is y=2x+(28)/(sqrt(x))