What is the derivative of (x^2-3/(x+1)) ?

The derivative of (x^2-3/(x+1)) is (x^2+2x+3)/((x+1)^2)

What is the first derivative of (x^2-3/(x+1)) ?

The first derivative of (x^2-3/(x+1)) is (x^2+2x+3)/((x+1)^2)

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\frac{d}{d x} (\frac{x ^{2} - 3}{x + 1})

\frac{x ^{2} + 2 x + 3}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 3}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 3 ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) ( x ^{2} - 3 )}{( x + 1 ) ^{2}}

\frac{d}{d x} (x^{2} - 3) = 2 x

\frac{d}{d x} (x + 1) = 1

= \frac{2 x ( x + 1 ) - 1 \cdot ( x ^{2} - 3 )}{( x + 1 ) ^{2}}

Simplify

\frac{2 x ( x + 1 ) - 1 \cdot ( x ^{2} - 3 )}{( x + 1 ) ^{2}} : \frac{x ^{2} + 2 x + 3}{( x + 1 ) ^{2}}

= \frac{x ^{2} + 2 x + 3}{( x + 1 ) ^{2}}

x = 1 \sum \infty x^{3} e^{- x^{2}}

y^{^{''}} + 64 y = 0, y (0) = 2, y^{^{'}} (0) = 1

(- x y sin (x) + 2 y cos (x)) d x + (2 x cos (x)) d y = 0

t^{2} e^{- 3 t} sin (4 t)

What is the derivative of (x^2-3/(x+1)) ?
The derivative of (x^2-3/(x+1)) is (x^2+2x+3)/((x+1)^2)
What is the first derivative of (x^2-3/(x+1)) ?
The first derivative of (x^2-3/(x+1)) is (x^2+2x+3)/((x+1)^2)