What is area y=x^2-1,y=-x+2 ?

The answer to area y=x^2-1,y=-x+2 is 3sqrt(13)-(5sqrt(13))/6

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area y=x^2-1,y=-x+2

area

y = x^{2} - 1, y = - x + 2

313 - \frac{5 13}{6}

Decimal Notation

7.81202 \dots

Solution steps

Apply the area formula:

\int_{\frac{- 1 - 13}{2}}^{\frac{- 1 + 13}{2}} x^{2} - 1 - (- x + 2) d x

Solve

\int_{\frac{- 1 - 13}{2}}^{\frac{- 1 + 13}{2}} x^{2} - 1 - (- x + 2) d x : 313 - \frac{5 13}{6}

The area is:

= 313 - \frac{5 13}{6}

\int 2 x^{2} x d x

h \to 0 lim (\frac{1 + h}{h})

\int_{0}^{π} 1

\int \frac{5 x - 1}{x ^{2} ( 2 x - 1 )} d x

\frac{s + 2}{2 s \cdot ( s + 1 )}

What is area y=x^2-1,y=-x+2 ?
The answer to area y=x^2-1,y=-x+2 is 3sqrt(13)-(5sqrt(13))/6