What is (\partial)/(\partial x)(ln(4x-7y)) ?

The answer to (\partial)/(\partial x)(ln(4x-7y)) is 4/(4x-7y)

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(\partial)/(\partial x)(ln(4x-7y))

\frac{\partial}{\partial x} (ln (4 x - 7 y))

\frac{4}{4 x - 7 y}

Solution steps

\frac{\partial}{\partial x} (ln (4 x - 7 y))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{4 x - 7 y} \frac{\partial}{\partial x} (4 x - 7 y)

= \frac{1}{4 x - 7 y} \frac{\partial}{\partial x} (4 x - 7 y)

\frac{\partial}{\partial x} (4 x - 7 y) = 4

= \frac{1}{4 x - 7 y} \cdot 4

Simplify

\frac{1}{4 x - 7 y} \cdot 4 : \frac{4}{4 x - 7 y}

= \frac{4}{4 x - 7 y}

(e^{x^{'}})^{^{'}}

\int - \frac{1}{x} + c d x

f (x) = - 7 x^{2} + 3 x, at x = 4

x \to 2 lim (x^{2} - 2 x)

4 x^{2} y^{^{''}} + 8 x y^{^{'}} - 3 y = 0

What is (\partial)/(\partial x)(ln(4x-7y)) ?
The answer to (\partial)/(\partial x)(ln(4x-7y)) is 4/(4x-7y)