What is (\partial)/(\partial x)(12cos(6x)cos(4y)) ?

The answer to (\partial)/(\partial x)(12cos(6x)cos(4y)) is -72sin(6x)cos(4y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(12cos(6x)cos(4y))

\frac{\partial}{\partial x} (12 cos (6 x) cos (4 y))

- 72 sin (6 x) cos (4 y)

Solution steps

\frac{\partial}{\partial x} (12 cos (6 x) cos (4 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 12 cos (4 y) \frac{\partial}{\partial x} (cos (6 x))

Apply the chain rule:

- sin (6 x) \frac{\partial}{\partial x} (6 x)

= - sin (6 x) \frac{\partial}{\partial x} (6 x)

\frac{\partial}{\partial x} (6 x) = 6

= 12 cos (4 y) (- sin (6 x) \cdot 6)

Simplify

= - 72 sin (6 x) cos (4 y)

\int_{0}^{3} \frac{1}{x + 1} d x

y = \frac{7}{x + 5}

\int (x - 4)^{2} d x

x \to 0 + lim ((x + 1)^{I n x})

\int \frac{( ln ( x ) )}{x ^{3}} d x

What is (\partial)/(\partial x)(12cos(6x)cos(4y)) ?
The answer to (\partial)/(\partial x)(12cos(6x)cos(4y)) is -72sin(6x)cos(4y)