What is the solution for t^2y^{''}-3ty^'-21y=0 ?

The solution for t^2y^{''}-3ty^'-21y=0 is y=c_{1}t^7+(c_{2})/(t^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t^2y^{''}-3ty^'-21y=0

t^{2} y^{^{''}} - 3 t y^{^{'}} - 21 y = 0

y = c_{1} t^{7} + \frac{c _{2}}{t ^{3}}

Solution steps

t^{2} y^{''} (t) - 3 t y^{'} (t) - 21 y = 0

Solve linear ODE:

y = c_{1} t^{7} + \frac{c _{2}}{t ^{3}}

y = c_{1} t^{7} + \frac{c _{2}}{t ^{3}}

\frac{\partial}{\partial y} (x^{2} y e^{\frac{y}{z}})

\frac{\partial}{\partial x} (3 x sin (7 x^{2} y))

\frac{\partial}{\partial x} (x e^{y} - y e^{x})

\int_{0}^{1} \frac{3 ^{3 x} - 1}{3 ^{x}} d x

y = (2 x + 1) + \frac{2}{( 2 x + 1 ) ^{3}}

What is the solution for t^2y^{''}-3ty^'-21y=0 ?
The solution for t^2y^{''}-3ty^'-21y=0 is y=c_{1}t^7+(c_{2})/(t^3)