What is the solution for 2xydy=(y^2+1)dx ?

The solution for 2xydy=(y^2+1)dx is y=sqrt(c_{1)x-1},y=-sqrt(c_{1)x-1}

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2xydy=(y^2+1)dx

2 x y d y = (y^{2} + 1) d x

y = c_{1} x - 1, y = - c_{1} x - 1

Solution steps

2 x y d y = (y^{2} + 1) d x

Solve separable ODE:

y = c_{1} x - 1, y = - c_{1} x - 1

y = c_{1} x - 1, y = - c_{1} x - 1

\frac{d}{d x} (\frac{3 x}{7})

\int e^{2 x} (1 - 7 e^{2 x})^{2} d x

\int \frac{175}{e ^{- x} + 1} d x

\frac{d}{d x} (ln (7) x^{2})

f (x) = (3 x + 1) (x^{2} - 2)

What is the solution for 2xydy=(y^2+1)dx ?
The solution for 2xydy=(y^2+1)dx is y=sqrt(c_{1)x-1},y=-sqrt(c_{1)x-1}